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信頼的App-Development-with-Swift-Certified-User|効率的なApp-Development-with-Swift-Certified-User日本語版試験|試験の準備方法App Development with Swift Certified User Exam関連資格知識
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Apple App Development with Swift Certified User Exam 認定 App-Development-with-Swift-Certified-User 試験問題 (Q23-Q28):
質問 # 23
Review the code snippet and then predict the output.
- A. Total count: 20
- B. Total count: 9
- C. Total count: 10
- D. Total count: 11
正解:C
解説:
This question belongs to Swift Programming Language , especially the domains covering control flow , loops , logical operators , and guard . The loop runs through 0.. < max, and since max = 101, the values of num are 0 through 100. Inside the loop, the guard statement keeps only values that satisfy both conditions:
* num % 5 == 0 # the number must be divisible by 5
* num % 2 != 0 # the number must be odd
So the code counts numbers from 0 to 100 that are odd multiples of 5 . Those values are:
5, 15, 25, 35, 45, 55, 65, 75, 85, 95
That gives a total of 10 numbers. Therefore count becomes 10, and the printed output is:
Total count: 10
The key Swift concept here is that guard ... else { continue } skips any loop iteration that does not meet the required condition. Only matching values reach count += 1. This is a standard use of guard for early exit and of the remainder operator % for divisibility checks. Therefore, the correct answer is B .
質問 # 24
For each statement about Navigation in SwiftUI. select True or False.
正解:
解説:
Explanation:
* You can treat a NavigationLink like a button, and run some Swift code when it is pressed. - False
* NavigationSplitView can be used to do navigation differently on different device sizes. - True
* You can put a header on your present View in a NavigationStack using .navigationTitle. - True
* If you have a NavigationLink that goes to another View with a NavigationLink, you need to declare a NavigationStack at each level. - False This question belongs to View Building with SwiftUI , specifically the objective on creating a multi-view app with navigation stacks, links, and sheets . Statement 1 is False because NavigationLink is primarily a navigation control that pushes or presents a destination in a navigation container; Apple documents it as creating a navigation link that presents a destination, not as a general-purpose action control like Button.
Statement 2 is True because NavigationSplitView is designed for adaptive navigation and can present navigation in different ways depending on platform and available space. Apple documents NavigationSplitView as a container for navigation across multiple columns, and this adaptive behavior is exactly why it is used differently across device sizes.
Statement 3 is True because .navigationTitle(...) sets the navigation title for a view shown inside a navigation container. Apple explicitly describes a view's navigation title as something used to visually display the current navigation state of an interface.
Statement 4 is False because you do not need a separate NavigationStack at every level. Apple describes NavigationStack as the container that manages a stack of views, and NavigationLink pushes additional destinations onto that stack. Nested destinations can keep navigating within the same stack.
質問 # 25
Review the code.
var capitalCities = [ " USA " : " Washington D.C. " , " Spain " : " Madrid " , " Peru " : " Lima " ] Which two statements add the capital city of " Italy " to the dictionary? (Choose 2.)
- A. capitalCities.append([ " Italy " : " Rome " ])
- B. capitalCities = capitalCities + [ " Italy " : " Rome " ]
- C. capitalCities.updateValue( " Rome " , forKey: " Italy " )
- D. capitalCities[ " Italy " ] = " Rome "
- E. capitalCities[ " Rome " ] = " Italy "
正解:C、D
解説:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question falls under Swift Programming Language , specifically the domain for managing data using collection types , with emphasis on dictionaries . In Swift, a dictionary stores data as key-value pairs , so in this example the country name is the key and the capital city is the value. To add a new entry, Swift supports two standard approaches. The first is subscript assignment , which is shown in option C : capitalCities[ " Italy " ] = " Rome " . Apple's documentation explains that you can add a key-value pair to a dictionary by assigning a value for a new key through the dictionary subscript.
The second correct approach is option E : capitalCities.updateValue( " Rome " , forKey: " Italy " ). Apple documents that updateValue(_:forKey:) updates the value for an existing key, or adds a new key-value pair if the key does not already exist . That makes it equally valid for inserting " Italy " : " Rome " into the dictionary.
The incorrect options fail for different reasons. A reverses the key and value, making " Rome " the key and " Italy " the value. B is wrong because append is used with arrays, not dictionaries. D is not the standard valid insertion syntax for Swift dictionaries in this context; Swift's documented mutation approaches here are subscript assignment and updateValue. Therefore, the two correct answers are C and E .
質問 # 26
You need to create a Watchpoint in Xcode. In which order should you complete the actions? Move all the actions to the answer area and place them in the correct order.
正解:
解説:
Explanation:
This question belongs to Xcode Developer Tools , specifically the objective on using debugging techniques including breakpoints, watchpoints, and logging to resolve errors . A watchpoint monitors a variable or memory location during a debugging session, so you first need the program to stop while being debugged.
That is why the correct order begins with setting a breakpoint and then running the code so execution pauses at a useful point. Apple's debugging guidance describes debugging as something done at runtime using the debugger, and LLDB's watchpoint documentation explains that watchpoints are part of the debugger workflow rather than something you set before the program is stopped.
Once execution is paused, you use the debug area to inspect the current variables. After locating the variable you want to monitor, you right-click the variable and select Watch to create the watchpoint. This sequence is consistent with how Xcode and LLDB expose watchpoint functionality during an active debug session.
LLDB also describes watchpoints as objects you create to stop execution when a watched value changes, which only makes sense after the debugger has access to the running program state.
質問 # 27
Complete the code that conforms to the View protocol by selecting the correct option from each drop-down list.
Note: You will receive partial credit for each correct answer.
正解:
解説:
Explanation:
This question belongs to View Building with SwiftUI , especially the domain covering positioning and/or layout a single SwiftUI View with standard Views and modifiers and the foundational structure of a SwiftUI view. In SwiftUI, a custom screen is typically declared as a struct that conforms to the View protocol. Apple's SwiftUI documentation shows the standard pattern:
struct ScreenView: View {
var body: some View {
Text( " Hello " )
}
}
Here, struct is required because SwiftUI views are commonly defined as structures. View is required after the colon because the type must conform to the View protocol. body is the required computed property that returns the content of the view as some View. Apple documents that every conforming View type must provide a body property that describes its content.
So the completed code is:
import SwiftUI
struct ScreenView: View {
var body: some View {
Text( " Hello " )
}
}
This is the canonical SwiftUI view declaration pattern and is one of the most fundamental concepts in App Development with Swift.
質問 # 28
......
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